1.)5g=__mg
2.)875mg=__g
3.)15kg=__g
4.)25000mg=__g
5.)85cg=__mg​

there is only one way to arrange all the eight [tex]b's[/tex] relative to each other because they are not distinct. we have

  [tex]\underline{\ \ }b\underline{\ \ }b\underline{\ \ }b\underline{\ \ }b\underline{\ \ }b\underline{\ \ }b\underline{\ \ }b\underline{\ \ }b\underline{\ \ }[/tex]

now there are nine places to place an [tex]a[/tex] (and not more than one [tex]a[/tex] in one place).   because we have four [tex]a[/tex] symbols, we need to choose four of these nine places to insert an [tex]a[/tex]. order does not matter because the [tex]a[/tex] are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

  [tex]1\cdot c(9,4) = \dfrac{9! }{4! (9-4)! } = \dfrac{9\cdot8\cdot7\cdot6\cdot5! }{4! 5! } = \dfrac{9\cdot8\cdot7\cdot6}{4\cdot3\cdot2\cdot1} = 126.[/tex]

thus there are 126 ways to form such "words."

345

step-by-step explanation:

step-by-step explanation:

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