Find p(-2) if p(x)=3x^3 -x^2 +2x-5. What does this tell you about the factors of p(x)

Mathematics

canyonrico05 · 25.02.2021 15:40

ANSWER(S): 2 Show answers 8 Сomment

ANSWER(S)

answered: DefineSilver3837

25.06.2019 09:30

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

answered: aleiahmartin

25.06.2019 00:30

Teri ma ki chhut‌‌‌‌‌‌

answered: werdtotheblue691

22.06.2019 20:30

step-by-step explanation:

how many centimeters did the level of the salsa go down by?

answered: ashley968

25.02.2021 15:40

$\boxed{\textsf{ The value of the polynomial at p = (-2) is \textbf{ -37}.}}$

Step-by-step explanation:

A polynomial is given to us and we need to find its value at p = (-2) . The given polynomial is :-

$\sf\implies p(x)= 3x^3 -x^2 +2x-5$

Also second part of the question says what does this tell about the factors of p(x) .

On putting p = (-2) :-

$\sf \implies p(x)= 3x^3 -x^2 +2x-5 \\\\\sf\implies p(-2) = 3 (-2)^3-(-2)^2+2(-2)-5 \\\\\sf\implies p(-2)= 3\times (-8) -4 -4 -5 \\\\\sf\implies p(-2)=-24-4-4-5 \\\\\implies \boxed{ \pink{\sf p(-2)= (-37) }}$

Now this tells us that ( x + 2 ) is not a factor of the given polynomial. When we divide the given polynomial by (x + 2) then the remainder will be -37 .

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