What is an equation of the line that passes through the points (-8, 2) and (-4,-3)? Answer Submit Answer attempt 1 out of 2 Policy Terms of Service

francisco42002   ·   18.10.2021 03:30
27.06.2019 21:20

9x

[tex]7 {}^{6} 7 {}^{3} = [/tex]

23.06.2019 11:00

its the fourth option 22.06.2019 10:00

paula, cory, and krista

18.10.2021 03:30

There are two features in the question to help you decide the approach; they are "line" and "parallel". Because it is a line, it will have a "slope"; and, because the lines are parallel, they will have the same slope. Therefore, 1. Find the slope of the known line (-3,-4) and (2,8), next 2. Assign that slope to the second line and then 3. use the slope and the point (-2,5) on the second (parallel) line to determine the second point on the unknown parallel line. Put simply: get the slope of the first line, which is the slope of the second line, then find the missing point for the second line.

Get the slope: slope = (y2-y1)/(x2-x1) = (8-(-4))/(2-(-3)) = 12/5

Set the slope equal to the unknown line having point (-2,5): (y2-y1)/(x2-x1)=(y2-5)/(x2-(-2) = 12/5

Solve both equations: y2 - 5 = 12, y2 = 18 and x2 + 2 = 5, x2 = 3 therefore the point is (3,18)

So the parallel line is (-2,5) (3,18). If you graph it, you will see it is parallel to (-3,-4) (2,8). I hope the helps.

18.10.2021 03:30

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