Nuka is weaving beaded strips. The double number line shows that they can weave
\[7 \,\text{cm}\] of the strip in
\[4\] minutes.
A double number line with 6 equally spaced tick marks. The line labeled Time, minutes, reads from left to right: 0, three unlabeled tick marks, 4, an unlabeled tick mark. The line labeled Length, centimeters, reads from left to right: 0, three unlabeled tick marks, 7, an unlabeled tick mark.
\[0\]
\[4\]
\[4\]
\[0\]
\[7\]
\[7\]
A double number line with 6 equally spaced tick marks. The line labeled Time, minutes, reads from left to right: 0, three unlabeled tick marks, 4, an unlabeled tick mark. The line labeled Length, centimeters, reads from left to right: 0, three unlabeled tick marks, 7, an unlabeled tick mark.
Based on the ratio shown in the double number line, what length can Nuka weave in
\[5\] minutes?

step-by-step explanation:

infinity is the answer

2nd one in the first row is correct

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.